1)Mass/Mr = 9.7/(65+32)
=0.1mol
0.1 x 2 = 0.2mol
0.2mol x 24dm^3 = 4.8dm^3
ANS: D
2)Looking at reaction, we would need the mole ratio of 2 to 1
1.0/100=0.01mol
0.01mol x 2 = 0.002mol
0.02mol/1.0mol/dm^3 = 0.02dm^3
= 20cm^3
ANS : B
-Alson
The online home to Greg Alson and somewhat 'ok' works as put by one of his pals but that is another story.
1)Mass/Mr = 9.7/(65+32)
=0.1mol
0.1 x 2 = 0.2mol
0.2mol x 24dm^3 = 4.8dm^3
ANS: D
2)Looking at reaction, we would need the mole ratio of 2 to 1
1.0/100=0.01mol
0.01mol x 2 = 0.002mol
0.02mol/1.0mol/dm^3 = 0.02dm^3
= 20cm^3
ANS : B
-Alson
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